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3111144541 is a prime number
BaseRepresentation
bin1011100101110000…
…0100110001011101
322000211011111222121
42321130010301131
522332423111131
61232414342541
7140045202151
oct27134046135
98024144877
103111144541
111357183a3a
12729abaa51
133a772a83b
14217299061
151331ea911
hexb9704c5d

3111144541 has 2 divisors, whose sum is σ = 3111144542. Its totient is φ = 3111144540.

The previous prime is 3111144481. The next prime is 3111144559. The reversal of 3111144541 is 1454411113.

3111144541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3044722041 + 66422500 = 55179^2 + 8150^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3111144541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111144241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555572270 + 1555572271.

It is an arithmetic number, because the mean of its divisors is an integer number (1555572271).

Almost surely, 23111144541 is an apocalyptic number.

It is an amenable number.

3111144541 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111144541 is an equidigital number, since it uses as much as digits as its factorization.

3111144541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 960, while the sum is 25.

The square root of 3111144541 is about 55777.6347741637. The cubic root of 3111144541 is about 1459.8449420929.

Adding to 3111144541 its reverse (1454411113), we get a palindrome (4565555654).

The spelling of 3111144541 in words is "three billion, one hundred eleven million, one hundred forty-four thousand, five hundred forty-one".