Search a number
-
+
31112013414733 is a prime number
BaseRepresentation
bin1110001001011110101001…
…00000100000000101001101
311002011021112201010020010021
413010233110200200011031
513034214400413232413
6150100354525542141
76360524460431416
oct704572440400515
9132137481106107
1031112013414733
119a05592536379
1235a5872414951
131448b09097c44
14797b8816480d
1538e46529a18d
hex1c4bd482014d

31112013414733 has 2 divisors, whose sum is σ = 31112013414734. Its totient is φ = 31112013414732.

The previous prime is 31112013414641. The next prime is 31112013414793. The reversal of 31112013414733 is 33741431021113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22029252022089 + 9082761392644 = 4693533^2 + 3013762^2 .

It is a cyclic number.

It is not a de Polignac number, because 31112013414733 - 29 = 31112013414221 is a prime.

It is a super-2 number, since 2×311120134147332 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31112013414793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556006707366 + 15556006707367.

It is an arithmetic number, because the mean of its divisors is an integer number (15556006707367).

Almost surely, 231112013414733 is an apocalyptic number.

It is an amenable number.

31112013414733 is a deficient number, since it is larger than the sum of its proper divisors (1).

31112013414733 is an equidigital number, since it uses as much as digits as its factorization.

31112013414733 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 34.

Adding to 31112013414733 its reverse (33741431021113), we get a palindrome (64853444435846).

The spelling of 31112013414733 in words is "thirty-one trillion, one hundred twelve billion, thirteen million, four hundred fourteen thousand, seven hundred thirty-three".