3111204401 has 2 divisors, whose sum is σ = 3111204402. Its totient is φ = 3111204400.

The previous prime is 3111204337. The next prime is 3111204409. The reversal of 3111204401 is 1044021113.

It is a happy number.

3111204401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2554291600 + 556912801 = 50540^2 + 23599^2 .

It is an emirp because it is prime and its reverse (1044021113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3111204401 - 2⁶ = 3111204337 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3111204401.

It is not a weakly prime, because it can be changed into another prime (3111204409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555602200 + 1555602201.

It is an arithmetic number, because the mean of its divisors is an integer number (1555602201).

Almost surely, 2^3111204401 is an apocalyptic number.

It is an amenable number.

3111204401 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111204401 is an equidigital number, since it uses as much as digits as its factorization.

3111204401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 3111204401 is about 55778.1713665839. The cubic root of 3111204401 is about 1459.8543047520.

Adding to 3111204401 its reverse (1044021113), we get a palindrome (4155225514).

The spelling of 3111204401 in words is "three billion, one hundred eleven million, two hundred four thousand, four hundred one".