3111213101 has 2 divisors, whose sum is σ = 3111213102. Its totient is φ = 3111213100.

The previous prime is 3111213097. The next prime is 3111213137. The reversal of 3111213101 is 1013121113.

It is a happy number.

3111213101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2511012100 + 600201001 = 50110^2 + 24499^2 .

It is an emirp because it is prime and its reverse (1013121113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3111213101 - 2² = 3111213097 is a prime.

It is a super-3 number, since 3×3111213101³ (a number of 29 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111213601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555606550 + 1555606551.

It is an arithmetic number, because the mean of its divisors is an integer number (1555606551).

Almost surely, 2^3111213101 is an apocalyptic number.

It is an amenable number.

3111213101 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111213101 is an equidigital number, since it uses as much as digits as its factorization.

3111213101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 14.

The square root of 3111213101 is about 55778.2493540269. The cubic root of 3111213101 is about 1459.8556655027.

Adding to 3111213101 its reverse (1013121113), we get a palindrome (4124334214).

The spelling of 3111213101 in words is "three billion, one hundred eleven million, two hundred thirteen thousand, one hundred one".