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31112221212133 is a prime number
BaseRepresentation
bin1110001001011111000001…
…11001001011110111100101
311002011022002012010102120021
413010233200321023313211
513034220312112242013
6150100431311435141
76360532562612635
oct704574071136745
9132138065112507
1031112221212133
119a05689864666
1235a590bb25ab1
131448b40152399
14797ba79b66c5
1538e478644a8d
hex1c4be0e4bde5

31112221212133 has 2 divisors, whose sum is σ = 31112221212134. Its totient is φ = 31112221212132.

The previous prime is 31112221212113. The next prime is 31112221212161. The reversal of 31112221212133 is 33121212221113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26422406514529 + 4689814697604 = 5140273^2 + 2165598^2 .

It is a cyclic number.

It is not a de Polignac number, because 31112221212133 - 217 = 31112221081061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31112221212098 and 31112221212107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31112221212113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556110606066 + 15556110606067.

It is an arithmetic number, because the mean of its divisors is an integer number (15556110606067).

Almost surely, 231112221212133 is an apocalyptic number.

It is an amenable number.

31112221212133 is a deficient number, since it is larger than the sum of its proper divisors (1).

31112221212133 is an equidigital number, since it uses as much as digits as its factorization.

31112221212133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 864, while the sum is 25.

Adding to 31112221212133 its reverse (33121212221113), we get a palindrome (64233433433246).

The spelling of 31112221212133 in words is "thirty-one trillion, one hundred twelve billion, two hundred twenty-one million, two hundred twelve thousand, one hundred thirty-three".