Search a number
-
+
31112299997 is a prime number
BaseRepresentation
bin11100111110011100…
…000000010111011101
32222022021021121010022
4130332130000113131
51002204222044442
622143124321525
72150664120662
oct347634002735
988267247108
1031112299997
111221609a529
1260435432a5
132c1a96148c
141712069a69
15c215de3d2
hex73e7005dd

31112299997 has 2 divisors, whose sum is σ = 31112299998. Its totient is φ = 31112299996.

The previous prime is 31112299991. The next prime is 31112300027. The reversal of 31112299997 is 79999221113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24625769476 + 6486530521 = 156926^2 + 80539^2 .

It is a cyclic number.

It is not a de Polignac number, because 31112299997 - 214 = 31112283613 is a prime.

It is a super-2 number, since 2×311122999972 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31112299991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556149998 + 15556149999.

It is an arithmetic number, because the mean of its divisors is an integer number (15556149999).

Almost surely, 231112299997 is an apocalyptic number.

It is an amenable number.

31112299997 is a deficient number, since it is larger than the sum of its proper divisors (1).

31112299997 is an equidigital number, since it uses as much as digits as its factorization.

31112299997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 551124, while the sum is 53.

The spelling of 31112299997 in words is "thirty-one billion, one hundred twelve million, two hundred ninety-nine thousand, nine hundred ninety-seven".