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31113001319 is a prime number
BaseRepresentation
bin11100111110011110…
…101011100101100111
32222022022121020011012
4130332132223211213
51002204412020234
622143151332435
72151003101441
oct347636534547
988268536135
1031113001319
1112216529434
12604382111b
132c1ab4876a
1417121ad491
15c216cc0ce
hex73e7ab967

31113001319 has 2 divisors, whose sum is σ = 31113001320. Its totient is φ = 31113001318.

The previous prime is 31113001303. The next prime is 31113001357. The reversal of 31113001319 is 91310031113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 31113001319 - 24 = 31113001303 is a prime.

It is a super-2 number, since 2×311130013192 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 31113001294 and 31113001303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31113004319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556500659 + 15556500660.

It is an arithmetic number, because the mean of its divisors is an integer number (15556500660).

Almost surely, 231113001319 is an apocalyptic number.

31113001319 is a deficient number, since it is larger than the sum of its proper divisors (1).

31113001319 is an equidigital number, since it uses as much as digits as its factorization.

31113001319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 23.

The spelling of 31113001319 in words is "thirty-one billion, one hundred thirteen million, one thousand, three hundred nineteen".