Base | Representation |
---|---|
bin | 11100111110011110… |
… | …101011100101101000 |
3 | 2222022022121020011020 |
4 | 130332132223211220 |
5 | 1002204412020240 |
6 | 22143151332440 |
7 | 2151003101442 |
oct | 347636534550 |
9 | 88268536136 |
10 | 31113001320 |
11 | 12216529435 |
12 | 6043821120 |
13 | 2c1ab4876b |
14 | 17121ad492 |
15 | c216cc0d0 |
hex | 73e7ab968 |
31113001320 has 64 divisors (see below), whose sum is σ = 93381534720. Its totient is φ = 8293019904.
The previous prime is 31113001319. The next prime is 31113001357. The reversal of 31113001320 is 2310031113.
It is a super-2 number, since 2×311130013202 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 31113001320.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 210489 + ... + 326391.
It is an arithmetic number, because the mean of its divisors is an integer number (1459086480).
Almost surely, 231113001320 is an apocalyptic number.
31113001320 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31113001320 is an abundant number, since it is smaller than the sum of its proper divisors (62268533400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31113001320 is a wasteful number, since it uses less digits than its factorization.
31113001320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118154 (or 118150 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 31113001320 its reverse (2310031113), we get a palindrome (33423032433).
The spelling of 31113001320 in words is "thirty-one billion, one hundred thirteen million, one thousand, three hundred twenty".
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