Base | Representation |
---|---|
bin | 1001000011100001110… |
… | …00001001101100000101 |
3 | 1002202002021122102002001 |
4 | 10201300320021230011 |
5 | 20044144120211003 |
6 | 354533133545301 |
7 | 31323061243243 |
oct | 4416070115405 |
9 | 1082067572061 |
10 | 311131413253 |
11 | 10aa4a631891 |
12 | 50371345231 |
13 | 2345504807b |
14 | 110b765d793 |
15 | 815ea5a61d |
hex | 4870e09b05 |
311131413253 has 2 divisors, whose sum is σ = 311131413254. Its totient is φ = 311131413252.
The previous prime is 311131413239. The next prime is 311131413259. The reversal of 311131413253 is 352314131113.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 177326894404 + 133804518849 = 421102^2 + 365793^2 .
It is a cyclic number.
It is not a de Polignac number, because 311131413253 - 217 = 311131282181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311131413259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155565706626 + 155565706627.
It is an arithmetic number, because the mean of its divisors is an integer number (155565706627).
Almost surely, 2311131413253 is an apocalyptic number.
It is an amenable number.
311131413253 is a deficient number, since it is larger than the sum of its proper divisors (1).
311131413253 is an equidigital number, since it uses as much as digits as its factorization.
311131413253 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3240, while the sum is 28.
Adding to 311131413253 its reverse (352314131113), we get a palindrome (663445544366).
The spelling of 311131413253 in words is "three hundred eleven billion, one hundred thirty-one million, four hundred thirteen thousand, two hundred fifty-three".
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