Base | Representation |
---|---|
bin | 1110001001100001000010… |
… | …01101010100000001010111 |
3 | 11002011101212101111020010112 |
4 | 13010300201031110001113 |
5 | 13034230014324331411 |
6 | 150101130334513235 |
7 | 6360601404250202 |
oct | 704604115240127 |
9 | 132141771436115 |
10 | 31113300230231 |
11 | 9a0609294895a |
12 | 35a5b7136581b |
13 | 1448c82867a2b |
14 | 797c6b012939 |
15 | 38e4dd233b8b |
hex | 1c4c21354057 |
31113300230231 has 2 divisors, whose sum is σ = 31113300230232. Its totient is φ = 31113300230230.
The previous prime is 31113300230197. The next prime is 31113300230261. The reversal of 31113300230231 is 13203200331113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31113300230231 is a prime.
It is a super-2 number, since 2×311133002302312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31113300230197 and 31113300230206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31113300230261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556650115115 + 15556650115116.
It is an arithmetic number, because the mean of its divisors is an integer number (15556650115116).
Almost surely, 231113300230231 is an apocalyptic number.
31113300230231 is a deficient number, since it is larger than the sum of its proper divisors (1).
31113300230231 is an equidigital number, since it uses as much as digits as its factorization.
31113300230231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 31113300230231 its reverse (13203200331113), we get a palindrome (44316500561344).
The spelling of 31113300230231 in words is "thirty-one trillion, one hundred thirteen billion, three hundred million, two hundred thirty thousand, two hundred thirty-one".
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