Base | Representation |
---|---|
bin | 1001000011100001111… |
… | …11000001000111001101 |
3 | 1002202002102000212001021 |
4 | 10201300333001013031 |
5 | 20044200100310013 |
6 | 354533240314141 |
7 | 31323112450561 |
oct | 4416077010715 |
9 | 1082072025037 |
10 | 311133213133 |
11 | 10aa50651096 |
12 | 50371a72951 |
13 | 234555283a2 |
14 | 110b79ab6a1 |
15 | 815ecb3a8d |
hex | 4870fc11cd |
311133213133 has 2 divisors, whose sum is σ = 311133213134. Its totient is φ = 311133213132.
The previous prime is 311133213119. The next prime is 311133213151. The reversal of 311133213133 is 331312331113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 239044722084 + 72088491049 = 488922^2 + 268493^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311133213133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311133213098 and 311133213107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311133213113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155566606566 + 155566606567.
It is an arithmetic number, because the mean of its divisors is an integer number (155566606567).
Almost surely, 2311133213133 is an apocalyptic number.
It is an amenable number.
311133213133 is a deficient number, since it is larger than the sum of its proper divisors (1).
311133213133 is an equidigital number, since it uses as much as digits as its factorization.
311133213133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1458, while the sum is 25.
Adding to 311133213133 its reverse (331312331113), we get a palindrome (642445544246).
The spelling of 311133213133 in words is "three hundred eleven billion, one hundred thirty-three million, two hundred thirteen thousand, one hundred thirty-three".
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