Base | Representation |
---|---|
bin | 11100111110100000… |
… | …110000001100010111 |
3 | 2222022100121211012221 |
4 | 130332200300030113 |
5 | 1002210031410341 |
6 | 22143211123211 |
7 | 2151010523122 |
oct | 347640601427 |
9 | 88270554187 |
10 | 31113544471 |
11 | 1221686a519 |
12 | 6043a43507 |
13 | 2c1aca8a59 |
14 | 17122b13b9 |
15 | c21787ed1 |
hex | 73e830317 |
31113544471 has 2 divisors, whose sum is σ = 31113544472. Its totient is φ = 31113544470.
The previous prime is 31113544439. The next prime is 31113544543. The reversal of 31113544471 is 17444531113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31113544471 - 25 = 31113544439 is a prime.
It is a super-3 number, since 3×311135444713 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31113544421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556772235 + 15556772236.
It is an arithmetic number, because the mean of its divisors is an integer number (15556772236).
Almost surely, 231113544471 is an apocalyptic number.
31113544471 is a deficient number, since it is larger than the sum of its proper divisors (1).
31113544471 is an equidigital number, since it uses as much as digits as its factorization.
31113544471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20160, while the sum is 34.
The spelling of 31113544471 in words is "thirty-one billion, one hundred thirteen million, five hundred forty-four thousand, four hundred seventy-one".
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