Search a number
-
+
3111402157 is a prime number
BaseRepresentation
bin1011100101110100…
…0011101010101101
322000211122121100221
42321131003222231
522333004332112
61232424051341
7140050324213
oct27135035255
98024577327
103111402157
11135733a546
1272a003b51
133a77bab86
14217324cb3
1513324be07
hexb9743aad

3111402157 has 2 divisors, whose sum is σ = 3111402158. Its totient is φ = 3111402156.

The previous prime is 3111402143. The next prime is 3111402163. The reversal of 3111402157 is 7512041113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3041412201 + 69989956 = 55149^2 + 8366^2 .

It is an emirp because it is prime and its reverse (7512041113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3111402157 - 27 = 3111402029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111402857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555701078 + 1555701079.

It is an arithmetic number, because the mean of its divisors is an integer number (1555701079).

Almost surely, 23111402157 is an apocalyptic number.

It is an amenable number.

3111402157 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111402157 is an equidigital number, since it uses as much as digits as its factorization.

3111402157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 25.

The square root of 3111402157 is about 55779.9440390540. The cubic root of 3111402157 is about 1459.8852347708.

The spelling of 3111402157 in words is "three billion, one hundred eleven million, four hundred two thousand, one hundred fifty-seven".