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311144144330401 is a prime number
BaseRepresentation
bin100011010111110111110010…
…0001100100101111010100001
31111210200002102101120221110021
41012233233210030211322201
5311240241201422033101
63021425351401033441
7122352264644363554
oct10657574414457241
91453602371527407
10311144144330401
119015a543a66318
122aa919a0485881
131047c9c7ba4965
1456b9657ba069b
1525e888e9be5a1
hex11afbe4325ea1

311144144330401 has 2 divisors, whose sum is σ = 311144144330402. Its totient is φ = 311144144330400.

The previous prime is 311144144330399. The next prime is 311144144330407. The reversal of 311144144330401 is 104033441441113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 286654562127376 + 24489582203025 = 16930876^2 + 4948695^2 .

It is a cyclic number.

It is not a de Polignac number, because 311144144330401 - 21 = 311144144330399 is a prime.

Together with 311144144330399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (311144144330407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155572072165200 + 155572072165201.

It is an arithmetic number, because the mean of its divisors is an integer number (155572072165201).

Almost surely, 2311144144330401 is an apocalyptic number.

It is an amenable number.

311144144330401 is a deficient number, since it is larger than the sum of its proper divisors (1).

311144144330401 is an equidigital number, since it uses as much as digits as its factorization.

311144144330401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 311144144330401 its reverse (104033441441113), we get a palindrome (415177585771514).

The spelling of 311144144330401 in words is "three hundred eleven trillion, one hundred forty-four billion, one hundred forty-four million, three hundred thirty thousand, four hundred one".