Base | Representation |
---|---|
bin | 11100111110111001… |
… | …011000010010010111 |
3 | 2222022210202210202012 |
4 | 130332321120102113 |
5 | 1002213210001101 |
6 | 22144001334435 |
7 | 2151116431262 |
oct | 347671302227 |
9 | 88283683665 |
10 | 31120000151 |
11 | 1221a479799 |
12 | 604603741b |
13 | 2c1c429296 |
14 | 17130b1cd9 |
15 | c22110bbb |
hex | 73ee58497 |
31120000151 has 2 divisors, whose sum is σ = 31120000152. Its totient is φ = 31120000150.
The previous prime is 31120000133. The next prime is 31120000181. The reversal of 31120000151 is 15100002113.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31120000151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31120000181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560000075 + 15560000076.
It is an arithmetic number, because the mean of its divisors is an integer number (15560000076).
Almost surely, 231120000151 is an apocalyptic number.
31120000151 is a deficient number, since it is larger than the sum of its proper divisors (1).
31120000151 is an equidigital number, since it uses as much as digits as its factorization.
31120000151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 14.
Adding to 31120000151 its reverse (15100002113), we get a palindrome (46220002264).
The spelling of 31120000151 in words is "thirty-one billion, one hundred twenty million, one hundred fifty-one", and thus it is an aban number.
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