Base | Representation |
---|---|
bin | 100011011000010010011001… |
… | …1100110111100000111100111 |
3 | 1111210212112222110011102101121 |
4 | 1012300210303212330013213 |
5 | 311242210241132241012 |
6 | 3021511524141434411 |
7 | 122356360413016066 |
oct | 10660446346740747 |
9 | 1453775873142347 |
10 | 311201311212007 |
11 | 9018180a1a5617 |
12 | 2aaa0a9556ba07 |
13 | 104852086aa418 |
14 | 56bc31c28c1dd |
15 | 25ea0d8644a07 |
hex | 11b09339bc1e7 |
311201311212007 has 2 divisors, whose sum is σ = 311201311212008. Its totient is φ = 311201311212006.
The previous prime is 311201311211909. The next prime is 311201311212023. The reversal of 311201311212007 is 700212113102113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311201311212007 - 211 = 311201311209959 is a prime.
It is a super-2 number, since 2×3112013112120072 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311201311215007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155600655606003 + 155600655606004.
It is an arithmetic number, because the mean of its divisors is an integer number (155600655606004).
Almost surely, 2311201311212007 is an apocalyptic number.
311201311212007 is a deficient number, since it is larger than the sum of its proper divisors (1).
311201311212007 is an equidigital number, since it uses as much as digits as its factorization.
311201311212007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
The spelling of 311201311212007 in words is "three hundred eleven trillion, two hundred one billion, three hundred eleven million, two hundred twelve thousand, seven".
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