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31120313312113 is a prime number
BaseRepresentation
bin1110001001101110000110…
…01110000110001101110001
311002012001222010211200212221
413010313003032012031301
513034333400201441423
6150104250301321041
76361240242413104
oct704670316061561
9132161863750787
1031120313312113
119a090616180a3
1235a73a9b66181
13144982c7a121c
147983345b673b
1538e79dc83e5d
hex1c4dc3386371

31120313312113 has 2 divisors, whose sum is σ = 31120313312114. Its totient is φ = 31120313312112.

The previous prime is 31120313312051. The next prime is 31120313312129. The reversal of 31120313312113 is 31121331302113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31119126716304 + 1186595809 = 5578452^2 + 34447^2 .

It is a cyclic number.

It is not a de Polignac number, because 31120313312113 - 213 = 31120313303921 is a prime.

It is not a weakly prime, because it can be changed into another prime (31120313312173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560156656056 + 15560156656057.

It is an arithmetic number, because the mean of its divisors is an integer number (15560156656057).

Almost surely, 231120313312113 is an apocalyptic number.

It is an amenable number.

31120313312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31120313312113 is an equidigital number, since it uses as much as digits as its factorization.

31120313312113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 31120313312113 its reverse (31121331302113), we get a palindrome (62241644614226).

The spelling of 31120313312113 in words is "thirty-one trillion, one hundred twenty billion, three hundred thirteen million, three hundred twelve thousand, one hundred thirteen".