Base | Representation |
---|---|
bin | 1011100101111110… |
… | …1110000100001111 |
3 | 22000212222001210002 |
4 | 2321133232010033 |
5 | 22333144200421 |
6 | 1232451034515 |
7 | 140056262111 |
oct | 27137560417 |
9 | 8025861702 |
10 | 3112100111 |
11 | 135777696a |
12 | 72a29ba3b |
13 | 3a79a3773 |
14 | 2174673b1 |
15 | 133338b0b |
hex | b97ee10f |
3112100111 has 2 divisors, whose sum is σ = 3112100112. Its totient is φ = 3112100110.
The previous prime is 3112100107. The next prime is 3112100119. The reversal of 3112100111 is 1110012113.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3112100111 - 22 = 3112100107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3112100092 and 3112100101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3112100119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556050055 + 1556050056.
It is an arithmetic number, because the mean of its divisors is an integer number (1556050056).
Almost surely, 23112100111 is an apocalyptic number.
3112100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3112100111 is an equidigital number, since it uses as much as digits as its factorization.
3112100111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 11.
The square root of 3112100111 is about 55786.2000050192. The cubic root of 3112100111 is about 1459.9943877623.
Adding to 3112100111 its reverse (1110012113), we get a palindrome (4222112224).
The spelling of 3112100111 in words is "three billion, one hundred twelve million, one hundred thousand, one hundred eleven".
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