Base | Representation |
---|---|
bin | 101101010010010111110… |
… | …011101001010001101010 |
3 | 102000111212211020220201110 |
4 | 231102113303221101222 |
5 | 401442041411022310 |
6 | 10341402552331150 |
7 | 440561550623166 |
oct | 55222763512152 |
9 | 12014784226643 |
10 | 3112103220330 |
11 | a9a921154405 |
12 | 4231910a3ab6 |
13 | 1976159a4680 |
14 | aa8ab563ca6 |
15 | 55e462dcd20 |
hex | 2d497ce946a |
3112103220330 has 32 divisors (see below), whose sum is σ = 8043589862784. Its totient is φ = 766056177216.
The previous prime is 3112103220293. The next prime is 3112103220349. The reversal of 3112103220330 is 330223012113.
It is a junction number, because it is equal to n+sod(n) for n = 3112103220297 and 3112103220306.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3989875534 + ... + 3989876313.
It is an arithmetic number, because the mean of its divisors is an integer number (251362183212).
Almost surely, 23112103220330 is an apocalyptic number.
3112103220330 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3112103220330 is an abundant number, since it is smaller than the sum of its proper divisors (4931486642454).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3112103220330 is a wasteful number, since it uses less digits than its factorization.
3112103220330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7979751870.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 3112103220330 its reverse (330223012113), we get a palindrome (3442326232443).
The spelling of 3112103220330 in words is "three trillion, one hundred twelve billion, one hundred three million, two hundred twenty thousand, three hundred thirty".
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