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311212531141 is a prime number
BaseRepresentation
bin1001000011101011011…
…01100101110111000101
31002202021221021121220021
410201311231211313011
520044330401444031
6354545152335141
731325064603451
oct4416555456705
91082257247807
10311212531141
1110aa913a6966
12503945444b1
1323468aaa215
14110c4337661
158166c30511
hex4875b65dc5

311212531141 has 2 divisors, whose sum is σ = 311212531142. Its totient is φ = 311212531140.

The previous prime is 311212531079. The next prime is 311212531229. The reversal of 311212531141 is 141135212113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 180225720900 + 130986810241 = 424530^2 + 361921^2 .

It is a cyclic number.

It is not a de Polignac number, because 311212531141 - 211 = 311212529093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311212531541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155606265570 + 155606265571.

It is an arithmetic number, because the mean of its divisors is an integer number (155606265571).

Almost surely, 2311212531141 is an apocalyptic number.

It is an amenable number.

311212531141 is a deficient number, since it is larger than the sum of its proper divisors (1).

311212531141 is an equidigital number, since it uses as much as digits as its factorization.

311212531141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720, while the sum is 25.

Adding to 311212531141 its reverse (141135212113), we get a palindrome (452347743254).

The spelling of 311212531141 in words is "three hundred eleven billion, two hundred twelve million, five hundred thirty-one thousand, one hundred forty-one".