3112131332041 has 2 divisors, whose sum is σ = 3112131332042. Its totient is φ = 3112131332040.

The previous prime is 3112131332039. The next prime is 3112131332053. The reversal of 3112131332041 is 1402331312113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2029499406025 + 1082631926016 = 1424605^2 + 1040496^2 .

It is an emirp because it is prime and its reverse (1402331312113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3112131332041 - 2¹ = 3112131332039 is a prime.

It is a super-2 number, since 2×3112131332041² (a number of 26 digits) contains 22 as substring.

Together with 3112131332039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 3112131331997 and 3112131332015.

It is not a weakly prime, because it can be changed into another prime (3112131332441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556065666020 + 1556065666021.

It is an arithmetic number, because the mean of its divisors is an integer number (1556065666021).

Almost surely, 2^{3112131332041} is an apocalyptic number.

It is an amenable number.

3112131332041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112131332041 is an equidigital number, since it uses as much as digits as its factorization.

3112131332041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 3112131332041 its reverse (1402331312113), we get a palindrome (4514462644154).

The spelling of 3112131332041 in words is "three trillion, one hundred twelve billion, one hundred thirty-one million, three hundred thirty-two thousand, forty-one".