Base | Representation |
---|---|
bin | 100011011000011000011100… |
… | …1110100111010101100011011 |
3 | 1111210220210111200200122022122 |
4 | 1012300300321310322230123 |
5 | 311242413341403110441 |
6 | 3021521513110011455 |
7 | 122360330325444335 |
oct | 10660607164725433 |
9 | 1453823450618278 |
10 | 311214300441371 |
11 | 90187275293918 |
12 | 2aaa34bb646b8b |
13 | 104864c877a862 |
14 | 56bcbd1412455 |
15 | 25ea5e8b6a34b |
hex | 11b0c39d3ab1b |
311214300441371 has 2 divisors, whose sum is σ = 311214300441372. Its totient is φ = 311214300441370.
The previous prime is 311214300441337. The next prime is 311214300441419. The reversal of 311214300441371 is 173144003412113.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (173144003412113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311214300441371 is a prime.
It is not a weakly prime, because it can be changed into another prime (311214300441271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155607150220685 + 155607150220686.
It is an arithmetic number, because the mean of its divisors is an integer number (155607150220686).
Almost surely, 2311214300441371 is an apocalyptic number.
311214300441371 is a deficient number, since it is larger than the sum of its proper divisors (1).
311214300441371 is an equidigital number, since it uses as much as digits as its factorization.
311214300441371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 311214300441371 its reverse (173144003412113), we get a palindrome (484358303853484).
The spelling of 311214300441371 in words is "three hundred eleven trillion, two hundred fourteen billion, three hundred million, four hundred forty-one thousand, three hundred seventy-one".
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