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311214300441419 is a prime number
BaseRepresentation
bin100011011000011000011100…
…1110100111010101101001011
31111210220210111200200122101102
41012300300321310322231023
5311242413341403111134
63021521513110012015
7122360330325444434
oct10660607164725513
91453823450618342
10311214300441419
1190187275293961
122aaa34bb64700b
13104864c877a89b
1456bcbd141248b
1525ea5e8b6a37e
hex11b0c39d3ab4b

311214300441419 has 2 divisors, whose sum is σ = 311214300441420. Its totient is φ = 311214300441418.

The previous prime is 311214300441371. The next prime is 311214300441437. The reversal of 311214300441419 is 914144003412113.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311214300441419 is a prime.

It is a super-2 number, since 2×3112143004414192 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311214300441019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155607150220709 + 155607150220710.

It is an arithmetic number, because the mean of its divisors is an integer number (155607150220710).

Almost surely, 2311214300441419 is an apocalyptic number.

311214300441419 is a deficient number, since it is larger than the sum of its proper divisors (1).

311214300441419 is an equidigital number, since it uses as much as digits as its factorization.

311214300441419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 311214300441419 in words is "three hundred eleven trillion, two hundred fourteen billion, three hundred million, four hundred forty-one thousand, four hundred nineteen".