Base | Representation |
---|---|
bin | 1110001001110001011101… |
… | …11101111000010110001010 |
3 | 11002012020122010022202221101 |
4 | 13010320232331320112022 |
5 | 13034401100434002310 |
6 | 150105145514332014 |
7 | 6361333112461123 |
oct | 704705675702612 |
9 | 132166563282841 |
10 | 31122121000330 |
11 | 9a098a9a52aa8 |
12 | 35a781342a00a |
13 | 1449a5a153819 |
14 | 7984666d104a |
15 | 38e85780a43a |
hex | 1c4e2ef7858a |
31122121000330 has 64 divisors (see below), whose sum is σ = 56571613781760. Its totient is φ = 12326882033664.
The previous prime is 31122121000291. The next prime is 31122121000447. The reversal of 31122121000330 is 3300012122113.
It is a super-3 number, since 3×311221210003303 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31122121000298 and 31122121000307.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 509808789 + ... + 509869831.
It is an arithmetic number, because the mean of its divisors is an integer number (883931465340).
Almost surely, 231122121000330 is an apocalyptic number.
31122121000330 is a deficient number, since it is larger than the sum of its proper divisors (25449492781430).
31122121000330 is a wasteful number, since it uses less digits than its factorization.
31122121000330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62383.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 31122121000330 its reverse (3300012122113), we get a palindrome (34422133122443).
The spelling of 31122121000330 in words is "thirty-one trillion, one hundred twenty-two billion, one hundred twenty-one million, three hundred thirty", and thus it is an aban number.
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