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311221322201147 is a prime number
BaseRepresentation
bin100011011000011011101110…
…0010110110011100000111011
31111210221110122001100222220112
41012300313130112303200323
5311243022231440414042
63021525033542414535
7122360666330432231
oct10660673426634073
91453843561328815
10311221322201147
119018a24894a976
122aaa493b13144b
1310487077431bb7
1456bd299bd4951
1525ea8aa331982
hex11b0ddc5b383b

311221322201147 has 2 divisors, whose sum is σ = 311221322201148. Its totient is φ = 311221322201146.

The previous prime is 311221322201107. The next prime is 311221322201149. The reversal of 311221322201147 is 741102223122113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 311221322201147 - 244 = 293629136156731 is a prime.

It is a super-2 number, since 2×3112213222011472 (a number of 30 digits) contains 22 as substring.

Together with 311221322201149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (311221322201149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155610661100573 + 155610661100574.

It is an arithmetic number, because the mean of its divisors is an integer number (155610661100574).

Almost surely, 2311221322201147 is an apocalyptic number.

311221322201147 is a deficient number, since it is larger than the sum of its proper divisors (1).

311221322201147 is an equidigital number, since it uses as much as digits as its factorization.

311221322201147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 32.

The spelling of 311221322201147 in words is "three hundred eleven trillion, two hundred twenty-one billion, three hundred twenty-two million, two hundred one thousand, one hundred forty-seven".