Base | Representation |
---|---|
bin | 100011011000011011101110… |
… | …0010110110011100000111011 |
3 | 1111210221110122001100222220112 |
4 | 1012300313130112303200323 |
5 | 311243022231440414042 |
6 | 3021525033542414535 |
7 | 122360666330432231 |
oct | 10660673426634073 |
9 | 1453843561328815 |
10 | 311221322201147 |
11 | 9018a24894a976 |
12 | 2aaa493b13144b |
13 | 10487077431bb7 |
14 | 56bd299bd4951 |
15 | 25ea8aa331982 |
hex | 11b0ddc5b383b |
311221322201147 has 2 divisors, whose sum is σ = 311221322201148. Its totient is φ = 311221322201146.
The previous prime is 311221322201107. The next prime is 311221322201149. The reversal of 311221322201147 is 741102223122113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311221322201147 - 244 = 293629136156731 is a prime.
It is a super-2 number, since 2×3112213222011472 (a number of 30 digits) contains 22 as substring.
Together with 311221322201149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (311221322201149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155610661100573 + 155610661100574.
It is an arithmetic number, because the mean of its divisors is an integer number (155610661100574).
Almost surely, 2311221322201147 is an apocalyptic number.
311221322201147 is a deficient number, since it is larger than the sum of its proper divisors (1).
311221322201147 is an equidigital number, since it uses as much as digits as its factorization.
311221322201147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
The spelling of 311221322201147 in words is "three hundred eleven trillion, two hundred twenty-one billion, three hundred twenty-two million, two hundred one thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •