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31122231012133 is a prime number
BaseRepresentation
bin1110001001110001101011…
…00001100010101100100101
311002012020220210022221202121
413010320311201202230211
513034401312114342013
6150105204444305541
76361335616532212
oct704706541425445
9132166823287677
1031122231012133
119a09956062548
1235a78442422b1
131449a76b91371
1479847716ab09
1538e8622db58d
hex1c4e35862b25

31122231012133 has 2 divisors, whose sum is σ = 31122231012134. Its totient is φ = 31122231012132.

The previous prime is 31122231012109. The next prime is 31122231012137. The reversal of 31122231012133 is 33121013222113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27901562889249 + 3220668122884 = 5282193^2 + 1794622^2 .

It is a cyclic number.

It is not a de Polignac number, because 31122231012133 - 241 = 28923207756581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31122231012098 and 31122231012107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31122231012137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15561115506066 + 15561115506067.

It is an arithmetic number, because the mean of its divisors is an integer number (15561115506067).

Almost surely, 231122231012133 is an apocalyptic number.

It is an amenable number.

31122231012133 is a deficient number, since it is larger than the sum of its proper divisors (1).

31122231012133 is an equidigital number, since it uses as much as digits as its factorization.

31122231012133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 31122231012133 its reverse (33121013222113), we get a palindrome (64243244234246).

The spelling of 31122231012133 in words is "thirty-one trillion, one hundred twenty-two billion, two hundred thirty-one million, twelve thousand, one hundred thirty-three".