Base | Representation |
---|---|
bin | 100011011000011111110011… |
… | …1100111110001000000101111 |
3 | 1111210222022021212110212010011 |
4 | 1012300333213213301000233 |
5 | 311243143221342200221 |
6 | 3021533045025354051 |
7 | 122361430020212635 |
oct | 10660774747610057 |
9 | 1453868255425104 |
10 | 311230101131311 |
11 | 90192a4337805a |
12 | 2aaa658b198927 |
13 | 10487b4615b82b |
14 | 56bd88db01355 |
15 | 25eac20de11e1 |
hex | 11b0fe79f102f |
311230101131311 has 2 divisors, whose sum is σ = 311230101131312. Its totient is φ = 311230101131310.
The previous prime is 311230101131251. The next prime is 311230101131371. The reversal of 311230101131311 is 113131101032113.
It is a balanced prime because it is at equal distance from previous prime (311230101131251) and next prime (311230101131371).
It is a cyclic number.
It is not a de Polignac number, because 311230101131311 - 29 = 311230101130799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311230101131371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155615050565655 + 155615050565656.
It is an arithmetic number, because the mean of its divisors is an integer number (155615050565656).
Almost surely, 2311230101131311 is an apocalyptic number.
311230101131311 is a deficient number, since it is larger than the sum of its proper divisors (1).
311230101131311 is an equidigital number, since it uses as much as digits as its factorization.
311230101131311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 22.
Adding to 311230101131311 its reverse (113131101032113), we get a palindrome (424361202163424).
The spelling of 311230101131311 in words is "three hundred eleven trillion, two hundred thirty billion, one hundred one million, one hundred thirty-one thousand, three hundred eleven".
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