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311230153141 is a prime number
BaseRepresentation
bin1001000011101101100…
…00110100000110110101
31002202100011102220201221
410201312300310012311
520044344404400031
6354551022150341
731325400436525
oct4416660640665
91082304386657
10311230153141
1110aaa03425a6
125039a4223b1
132346c63a13b
14110c6803685
158168561a11
hex4876c341b5

311230153141 has 2 divisors, whose sum is σ = 311230153142. Its totient is φ = 311230153140.

The previous prime is 311230153111. The next prime is 311230153183. The reversal of 311230153141 is 141351032113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 290255872516 + 20974280625 = 538754^2 + 144825^2 .

It is an emirp because it is prime and its reverse (141351032113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311230153141 - 25 = 311230153109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311230153111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155615076570 + 155615076571.

It is an arithmetic number, because the mean of its divisors is an integer number (155615076571).

Almost surely, 2311230153141 is an apocalyptic number.

It is an amenable number.

311230153141 is a deficient number, since it is larger than the sum of its proper divisors (1).

311230153141 is an equidigital number, since it uses as much as digits as its factorization.

311230153141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 311230153141 its reverse (141351032113), we get a palindrome (452581185254).

The spelling of 311230153141 in words is "three hundred eleven billion, two hundred thirty million, one hundred fifty-three thousand, one hundred forty-one".