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311234424343 is a prime number
BaseRepresentation
bin1001000011101110000…
…01000110111000010111
31002202100110110220201121
410201313001012320113
520044402003034333
6354551253504411
731325451646153
oct4416701067027
91082313426647
10311234424343
1110aaa279a617
125039b942107
13234704a428b
14110c71d6063
158168b0732d
hex4877046e17

311234424343 has 2 divisors, whose sum is σ = 311234424344. Its totient is φ = 311234424342.

The previous prime is 311234424329. The next prime is 311234424349. The reversal of 311234424343 is 343424432113.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311234424343 is a prime.

It is a super-2 number, since 2×3112344243432 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311234424299 and 311234424308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311234424349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155617212171 + 155617212172.

It is an arithmetic number, because the mean of its divisors is an integer number (155617212172).

Almost surely, 2311234424343 is an apocalyptic number.

311234424343 is a deficient number, since it is larger than the sum of its proper divisors (1).

311234424343 is an equidigital number, since it uses as much as digits as its factorization.

311234424343 is an evil number, because the sum of its binary digits is even.

The product of its digits is 82944, while the sum is 34.

Adding to 311234424343 its reverse (343424432113), we get a palindrome (654658856456).

The spelling of 311234424343 in words is "three hundred eleven billion, two hundred thirty-four million, four hundred twenty-four thousand, three hundred forty-three".