Base | Representation |
---|---|
bin | 11100111111001101… |
… | …110000110100110101 |
3 | 2222100011211021111112 |
4 | 130333031300310311 |
5 | 1002221041443131 |
6 | 22144312044405 |
7 | 2151213024545 |
oct | 347715606465 |
9 | 88304737445 |
10 | 31125343541 |
11 | 12222499316 |
12 | 6047993705 |
13 | 2c2057a456 |
14 | 1713aa3325 |
15 | c2281902b |
hex | 73f370d35 |
31125343541 has 2 divisors, whose sum is σ = 31125343542. Its totient is φ = 31125343540.
The previous prime is 31125343499. The next prime is 31125343547. The reversal of 31125343541 is 14534352113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17570562916 + 13554780625 = 132554^2 + 116425^2 .
It is a cyclic number.
It is not a de Polignac number, because 31125343541 - 26 = 31125343477 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31125343498 and 31125343507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31125343547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15562671770 + 15562671771.
It is an arithmetic number, because the mean of its divisors is an integer number (15562671771).
Almost surely, 231125343541 is an apocalyptic number.
It is an amenable number.
31125343541 is a deficient number, since it is larger than the sum of its proper divisors (1).
31125343541 is an equidigital number, since it uses as much as digits as its factorization.
31125343541 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21600, while the sum is 32.
Adding to 31125343541 its reverse (14534352113), we get a palindrome (45659695654).
The spelling of 31125343541 in words is "thirty-one billion, one hundred twenty-five million, three hundred forty-three thousand, five hundred forty-one".
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