Base | Representation |
---|---|
bin | 11100111111011111… |
… | …100010011010001001 |
3 | 2222100111121000012002 |
4 | 130333133202122021 |
5 | 1002223240044311 |
6 | 22145000000345 |
7 | 2151300442322 |
oct | 347737423211 |
9 | 88314530162 |
10 | 31130003081 |
11 | 12225091081 |
12 | 60494600b5 |
13 | 2c2151c288 |
14 | 1714557449 |
15 | c22e3993b |
hex | 73f7e2689 |
31130003081 has 2 divisors, whose sum is σ = 31130003082. Its totient is φ = 31130003080.
The previous prime is 31130003071. The next prime is 31130003083. The reversal of 31130003081 is 18030003113.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30516945481 + 613057600 = 174691^2 + 24760^2 .
It is a cyclic number.
It is not a de Polignac number, because 31130003081 - 218 = 31129740937 is a prime.
It is a super-2 number, since 2×311300030812 (a number of 22 digits) contains 22 as substring.
Together with 31130003083, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31130003083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565001540 + 15565001541.
It is an arithmetic number, because the mean of its divisors is an integer number (15565001541).
Almost surely, 231130003081 is an apocalyptic number.
It is an amenable number.
31130003081 is a deficient number, since it is larger than the sum of its proper divisors (1).
31130003081 is an equidigital number, since it uses as much as digits as its factorization.
31130003081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 31130003081 its reverse (18030003113), we get a palindrome (49160006194).
The spelling of 31130003081 in words is "thirty-one billion, one hundred thirty million, three thousand, eighty-one".
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