Base | Representation |
---|---|
bin | 1011100110001100… |
… | …1010000011010001 |
3 | 22000221122211210121 |
4 | 2321203022003101 |
5 | 22333412014134 |
6 | 1232522230241 |
7 | 140100034105 |
oct | 27143120321 |
9 | 8027584717 |
10 | 3113001169 |
11 | 1358231943 |
12 | 72a655381 |
13 | 3a7c2a935 |
14 | 21761d905 |
15 | 133465ab4 |
hex | b98ca0d1 |
3113001169 has 2 divisors, whose sum is σ = 3113001170. Its totient is φ = 3113001168.
The previous prime is 3113001161. The next prime is 3113001187. The reversal of 3113001169 is 9611003113.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2982470544 + 130530625 = 54612^2 + 11425^2 .
It is a cyclic number.
It is not a de Polignac number, because 3113001169 - 23 = 3113001161 is a prime.
It is a super-2 number, since 2×31130011692 = 19381552556390733122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3113001161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556500584 + 1556500585.
It is an arithmetic number, because the mean of its divisors is an integer number (1556500585).
Almost surely, 23113001169 is an apocalyptic number.
It is an amenable number.
3113001169 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113001169 is an equidigital number, since it uses as much as digits as its factorization.
3113001169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
The square root of 3113001169 is about 55794.2754142394. The cubic root of 3113001169 is about 1460.1352800464.
The spelling of 3113001169 in words is "three billion, one hundred thirteen million, one thousand, one hundred sixty-nine".
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