Base | Representation |
---|---|
bin | 1011100110001100… |
… | …1010000100111101 |
3 | 22000221122211221121 |
4 | 2321203022010331 |
5 | 22333412020102 |
6 | 1232522230541 |
7 | 140100034321 |
oct | 27143120475 |
9 | 8027584847 |
10 | 3113001277 |
11 | 1358231a31 |
12 | 72a655451 |
13 | 3a7c2a9b9 |
14 | 21761d981 |
15 | 133465b37 |
hex | b98ca13d |
3113001277 has 2 divisors, whose sum is σ = 3113001278. Its totient is φ = 3113001276.
The previous prime is 3113001233. The next prime is 3113001329. The reversal of 3113001277 is 7721003113.
3113001277 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1766184676 + 1346816601 = 42026^2 + 36699^2 .
It is an emirp because it is prime and its reverse (7721003113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3113001277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3113001977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556500638 + 1556500639.
It is an arithmetic number, because the mean of its divisors is an integer number (1556500639).
Almost surely, 23113001277 is an apocalyptic number.
It is an amenable number.
3113001277 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113001277 is an equidigital number, since it uses as much as digits as its factorization.
3113001277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 882, while the sum is 25.
The square root of 3113001277 is about 55794.2763820806. The cubic root of 3113001277 is about 1460.1352969320.
The spelling of 3113001277 in words is "three billion, one hundred thirteen million, one thousand, two hundred seventy-seven".
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