311300212999 has 2 divisors, whose sum is σ = 311300213000. Its totient is φ = 311300212998.

The previous prime is 311300212997. The next prime is 311300213009. The reversal of 311300212999 is 999212003113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311300212999 - 2¹ = 311300212997 is a prime.

It is a super-2 number, since 2×311300212999² (a number of 24 digits) contains 22 as substring.

Together with 311300212997, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311300212997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155650106499 + 155650106500.

It is an arithmetic number, because the mean of its divisors is an integer number (155650106500).

Almost surely, 2^311300212999 is an apocalyptic number.

311300212999 is a deficient number, since it is larger than the sum of its proper divisors (1).

311300212999 is an equidigital number, since it uses as much as digits as its factorization.

311300212999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26244, while the sum is 40.

The spelling of 311300212999 in words is "three hundred eleven billion, three hundred million, two hundred twelve thousand, nine hundred ninety-nine".