Base | Representation |
---|---|
bin | 1110001010000000001101… |
… | …00001001011001100100010 |
3 | 11002020000001110212112002200 |
4 | 13011000012201023030202 |
5 | 13040013301233240224 |
6 | 150112534525354030 |
7 | 6362033135546643 |
oct | 705000641131442 |
9 | 132200043775080 |
10 | 31130032321314 |
11 | 9a12199761603 |
12 | 35a9260a08916 |
13 | 144a71b1b8044 |
14 | 7989b72b36ca |
15 | 38eb6c13a5c9 |
hex | 1c500684b322 |
31130032321314 has 96 divisors (see below), whose sum is σ = 71635032668160. Its totient is φ = 9736348816896.
The previous prime is 31130032321301. The next prime is 31130032321327. The reversal of 31130032321314 is 41312323003113.
31130032321314 is a `hidden beast` number, since 3 + 1 + 1 + 3 + 0 + 0 + 323 + 21 + 314 = 666.
It is an interprime number because it is at equal distance from previous prime (31130032321301) and next prime (31130032321327).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 262112557 + ... + 262231295.
It is an arithmetic number, because the mean of its divisors is an integer number (746198256960).
Almost surely, 231130032321314 is an apocalyptic number.
31130032321314 is a gapful number since it is divisible by the number (34) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 31130032321314, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (35817516334080).
31130032321314 is an abundant number, since it is smaller than the sum of its proper divisors (40505000346846).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31130032321314 is a wasteful number, since it uses less digits than its factorization.
31130032321314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121384 (or 121381 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 31130032321314 its reverse (41312323003113), we get a palindrome (72442355324427).
The spelling of 31130032321314 in words is "thirty-one trillion, one hundred thirty billion, thirty-two million, three hundred twenty-one thousand, three hundred fourteen".
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