Base | Representation |
---|---|
bin | 100011011001000110000000… |
… | …1000110100000101101000111 |
3 | 1111211021011000210220112222021 |
4 | 1012302030001012200231013 |
5 | 311301014222022000012 |
6 | 3022034453005144011 |
7 | 122400362603456656 |
oct | 10662140106405507 |
9 | 1454234023815867 |
10 | 311312133000007 |
11 | 90214809208167 |
12 | 2aaba46355b007 |
13 | 104927ba2183c9 |
14 | 56c383266d19d |
15 | 25ece2296a007 |
hex | 11b23011a0b47 |
311312133000007 has 2 divisors, whose sum is σ = 311312133000008. Its totient is φ = 311312133000006.
The previous prime is 311312132999993. The next prime is 311312133000049. The reversal of 311312133000007 is 700000331213113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 311312133000007 - 219 = 311312132475719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311312133000307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155656066500003 + 155656066500004.
It is an arithmetic number, because the mean of its divisors is an integer number (155656066500004).
Almost surely, 2311312133000007 is an apocalyptic number.
311312133000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
311312133000007 is an equidigital number, since it uses as much as digits as its factorization.
311312133000007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
The spelling of 311312133000007 in words is "three hundred eleven trillion, three hundred twelve billion, one hundred thirty-three million, seven", and thus it is an aban number.
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