311320020113231 has 2 divisors, whose sum is σ = 311320020113232. Its totient is φ = 311320020113230.

The previous prime is 311320020113227. The next prime is 311320020113233. The reversal of 311320020113231 is 132311020023113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 311320020113231 - 2² = 311320020113227 is a prime.

It is a super-4 number, since 4×311320020113231⁴ (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 311320020113233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 311320020113197 and 311320020113206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311320020113233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155660010056615 + 155660010056616.

It is an arithmetic number, because the mean of its divisors is an integer number (155660010056616).

Almost surely, 2^{311320020113231} is an apocalyptic number.

311320020113231 is a deficient number, since it is larger than the sum of its proper divisors (1).

311320020113231 is an equidigital number, since it uses as much as digits as its factorization.

311320020113231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 311320020113231 its reverse (132311020023113), we get a palindrome (443631040136344).

The spelling of 311320020113231 in words is "three hundred eleven trillion, three hundred twenty billion, twenty million, one hundred thirteen thousand, two hundred thirty-one".