Base | Representation |
---|---|
bin | 11100111111100111… |
… | …101010000000000010 |
3 | 2222100122121010121010 |
4 | 130333213222000002 |
5 | 1002224311200310 |
6 | 22145113341350 |
7 | 2151324515166 |
oct | 347747520002 |
9 | 88318533533 |
10 | 31132131330 |
11 | 12226305063 |
12 | 604a107856 |
13 | 2c21ab5bb1 |
14 | 171494cca6 |
15 | c2320a320 |
hex | 73f9ea002 |
31132131330 has 32 divisors (see below), whose sum is σ = 77293569600. Its totient is φ = 8015628992.
The previous prime is 31132131323. The next prime is 31132131353. The reversal of 31132131330 is 3313123113.
It is a super-2 number, since 2×311321313302 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31132131297 and 31132131306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17891160 + ... + 17892899.
It is an arithmetic number, because the mean of its divisors is an integer number (2415424050).
Almost surely, 231132131330 is an apocalyptic number.
31132131330 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
31132131330 is an abundant number, since it is smaller than the sum of its proper divisors (46161438270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31132131330 is a wasteful number, since it uses less digits than its factorization.
31132131330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35784098.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 31132131330 its reverse (3313123113), we get a palindrome (34445254443).
The spelling of 31132131330 in words is "thirty-one billion, one hundred thirty-two million, one hundred thirty-one thousand, three hundred thirty".
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