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3113252053 is a prime number
BaseRepresentation
bin1011100110010000…
…0111010011010101
322000222010120221121
42321210013103111
522333443031203
61232531443541
7140102130412
oct27144072325
98028116847
103113252053
11135839338a
1272a7565b1
133a7cb7ba2
14217687109
151334b50bd
hexb99074d5

3113252053 has 2 divisors, whose sum is σ = 3113252054. Its totient is φ = 3113252052.

The previous prime is 3113252047. The next prime is 3113252071. The reversal of 3113252053 is 3502523113.

3113252053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3111631524 + 1620529 = 55782^2 + 1273^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3113252053 is a prime.

It is a super-4 number, since 4×31132520534 (a number of 39 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3113252953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556626026 + 1556626027.

It is an arithmetic number, because the mean of its divisors is an integer number (1556626027).

Almost surely, 23113252053 is an apocalyptic number.

It is an amenable number.

3113252053 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113252053 is an equidigital number, since it uses as much as digits as its factorization.

3113252053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 3113252053 is about 55796.5236641137. The cubic root of 3113252053 is about 1460.1745042247.

Adding to 3113252053 its reverse (3502523113), we get a palindrome (6615775166).

The spelling of 3113252053 in words is "three billion, one hundred thirteen million, two hundred fifty-two thousand, fifty-three".