Base | Representation |
---|---|
bin | 1011100110010001… |
… | …0101110001001101 |
3 | 22000222020121020021 |
4 | 2321210111301031 |
5 | 22334001430214 |
6 | 1232533022141 |
7 | 140102465233 |
oct | 27144256115 |
9 | 8028217207 |
10 | 3113311309 |
11 | 1358423959 |
12 | 72a784951 |
13 | 3a8008b54 |
14 | 2176a0953 |
15 | 1334c7924 |
hex | b9915c4d |
3113311309 has 2 divisors, whose sum is σ = 3113311310. Its totient is φ = 3113311308.
The previous prime is 3113311277. The next prime is 3113311363. The reversal of 3113311309 is 9031133113.
3113311309 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2832581284 + 280730025 = 53222^2 + 16755^2 .
It is a cyclic number.
It is not a de Polignac number, because 3113311309 - 25 = 3113311277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3113312309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556655654 + 1556655655.
It is an arithmetic number, because the mean of its divisors is an integer number (1556655655).
Almost surely, 23113311309 is an apocalyptic number.
It is an amenable number.
3113311309 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113311309 is an equidigital number, since it uses as much as digits as its factorization.
3113311309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 25.
The square root of 3113311309 is about 55797.0546624103. The cubic root of 3113311309 is about 1460.1837682301.
The spelling of 3113311309 in words is "three billion, one hundred thirteen million, three hundred eleven thousand, three hundred nine".
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