Base | Representation |
---|---|
bin | 1110001010000110110000… |
… | …01110101011011011110110 |
3 | 11002020100010200022001211120 |
4 | 13011003120032223123312 |
5 | 13040043002434003430 |
6 | 150114320012244410 |
7 | 6362216260303512 |
oct | 705033016533366 |
9 | 132210120261746 |
10 | 31133550687990 |
11 | 9a13734793563 |
12 | 35a9a83170706 |
13 | 144ab5c0b550a |
14 | 798c2c693142 |
15 | 38ecc5e74610 |
hex | 1c50d83ab6f6 |
31133550687990 has 16 divisors (see below), whose sum is σ = 74720521651248. Its totient is φ = 8302280183456.
The previous prime is 31133550687959. The next prime is 31133550688061. The reversal of 31133550687990 is 9978605533113.
It is a Smith number, since the sum of its digits (60) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 518892511437 + ... + 518892511496.
It is an arithmetic number, because the mean of its divisors is an integer number (4670032603203).
Almost surely, 231133550687990 is an apocalyptic number.
31133550687990 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
31133550687990 is an abundant number, since it is smaller than the sum of its proper divisors (43586970963258).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31133550687990 is a wasteful number, since it uses less digits than its factorization.
31133550687990 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1037785022943.
The product of its (nonzero) digits is 18370800, while the sum is 60.
The spelling of 31133550687990 in words is "thirty-one trillion, one hundred thirty-three billion, five hundred fifty million, six hundred eighty-seven thousand, nine hundred ninety".
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