Base | Representation |
---|---|
bin | 100011011001010011100111… |
… | …0110111101000101111011111 |
3 | 1111211100221110100021112010011 |
4 | 1012302213032313220233133 |
5 | 311302004043340323124 |
6 | 3022100124410224051 |
7 | 122402446005455263 |
oct | 10662471667505737 |
9 | 1454327410245104 |
10 | 311341355011039 |
11 | 90226144284601 |
12 | 2ab04059a25027 |
13 | 104954963661b2 |
14 | 56c500563c0a3 |
15 | 25eda83118994 |
hex | 11b29cede8bdf |
311341355011039 has 2 divisors, whose sum is σ = 311341355011040. Its totient is φ = 311341355011038.
The previous prime is 311341355011031. The next prime is 311341355011091. The reversal of 311341355011039 is 930110553143113.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 311341355011039 - 23 = 311341355011031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311341355010992 and 311341355011010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311341355011031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155670677505519 + 155670677505520.
It is an arithmetic number, because the mean of its divisors is an integer number (155670677505520).
Almost surely, 2311341355011039 is an apocalyptic number.
311341355011039 is a deficient number, since it is larger than the sum of its proper divisors (1).
311341355011039 is an equidigital number, since it uses as much as digits as its factorization.
311341355011039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72900, while the sum is 40.
The spelling of 311341355011039 in words is "three hundred eleven trillion, three hundred forty-one billion, three hundred fifty-five million, eleven thousand, thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •