Base | Representation |
---|---|
bin | 11100111111110000… |
… | …000000011000101011 |
3 | 2222100210201100010022 |
4 | 130333300000120223 |
5 | 1002230341221141 |
6 | 22145232311055 |
7 | 2151352232513 |
oct | 347760003053 |
9 | 88323640108 |
10 | 31134320171 |
11 | 1222756a619 |
12 | 604a9a248b |
13 | 2c223a1276 |
14 | 1714d5c843 |
15 | c234ddb4b |
hex | 73fc0062b |
31134320171 has 2 divisors, whose sum is σ = 31134320172. Its totient is φ = 31134320170.
The previous prime is 31134320089. The next prime is 31134320197. The reversal of 31134320171 is 17102343113.
It is a happy number.
It is an a-pointer prime, because the next prime (31134320197) can be obtained adding 31134320171 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31134320171 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31134320171.
It is not a weakly prime, because it can be changed into another prime (31134320671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15567160085 + 15567160086.
It is an arithmetic number, because the mean of its divisors is an integer number (15567160086).
Almost surely, 231134320171 is an apocalyptic number.
31134320171 is a deficient number, since it is larger than the sum of its proper divisors (1).
31134320171 is an equidigital number, since it uses as much as digits as its factorization.
31134320171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 31134320171 its reverse (17102343113), we get a palindrome (48236663284).
The spelling of 31134320171 in words is "thirty-one billion, one hundred thirty-four million, three hundred twenty thousand, one hundred seventy-one".
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