3113553437 has 2 divisors, whose sum is σ = 3113553438. Its totient is φ = 3113553436.

The previous prime is 3113553397. The next prime is 3113553439. The reversal of 3113553437 is 7343553113.

3113553437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3111519961 + 2033476 = 55781^2 + 1426^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113553437 - 2¹⁰ = 3113552413 is a prime.

Together with 3113553439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3113553397 and 3113553406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3113553439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556776718 + 1556776719.

It is an arithmetic number, because the mean of its divisors is an integer number (1556776719).

Almost surely, 2^3113553437 is an apocalyptic number.

It is an amenable number.

3113553437 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113553437 is an equidigital number, since it uses as much as digits as its factorization.

3113553437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 56700, while the sum is 35.

The square root of 3113553437 is about 55799.2243404870. The cubic root of 3113553437 is about 1460.2216209829.

The spelling of 3113553437 in words is "three billion, one hundred thirteen million, five hundred fifty-three thousand, four hundred thirty-seven".