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311400414109997 is a prime number
BaseRepresentation
bin100011011001101111000111…
…1000100001110000100101101
31111211120120220021101121021122
41012303132033010032010231
5311303441022003004442
63022143213023510325
7122406636361514252
oct10663361704160455
91454516807347248
10311400414109997
11902491a06337a3
122ab135a07583a5
131049ac18ba8cb4
1456c7c09169429
15260038ce60dd2
hex11b378f10e12d

311400414109997 has 2 divisors, whose sum is σ = 311400414109998. Its totient is φ = 311400414109996.

The previous prime is 311400414109969. The next prime is 311400414110011. The reversal of 311400414109997 is 799901414004113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 306313738316041 + 5086675793956 = 17501821^2 + 2255366^2 .

It is a cyclic number.

It is not a de Polignac number, because 311400414109997 - 232 = 311396119142701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311400414109907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155700207054998 + 155700207054999.

It is an arithmetic number, because the mean of its divisors is an integer number (155700207054999).

Almost surely, 2311400414109997 is an apocalyptic number.

It is an amenable number.

311400414109997 is a deficient number, since it is larger than the sum of its proper divisors (1).

311400414109997 is an equidigital number, since it uses as much as digits as its factorization.

311400414109997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 979776, while the sum is 53.

The spelling of 311400414109997 in words is "three hundred eleven trillion, four hundred billion, four hundred fourteen million, one hundred nine thousand, nine hundred ninety-seven".