Base | Representation |
---|---|
bin | 1110001010010100101001… |
… | …11111000000010101010010 |
3 | 11002021001101200220100212000 |
4 | 13011022110333000111102 |
5 | 13040203243141043102 |
6 | 150121552243414430 |
7 | 6362602214200644 |
oct | 705122477002522 |
9 | 132231350810760 |
10 | 31141012440402 |
11 | 9a16913750597 |
12 | 35ab406084416 |
13 | 144b77ac71527 |
14 | 79933968a894 |
15 | 3900b109e01c |
hex | 1c5294fc0552 |
31141012440402 has 32 divisors (see below), whose sum is σ = 72844473547200. Its totient is φ = 9834003928224.
The previous prime is 31141012440347. The next prime is 31141012440409. The reversal of 31141012440402 is 20404421014113.
31141012440402 is a `hidden beast` number, since 3 + 1 + 1 + 4 + 10 + 1 + 244 + 0 + 402 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (31141012440409) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15175930963 + ... + 15175933014.
It is an arithmetic number, because the mean of its divisors is an integer number (2276389798350).
Almost surely, 231141012440402 is an apocalyptic number.
31141012440402 is an abundant number, since it is smaller than the sum of its proper divisors (41703461106798).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31141012440402 is a wasteful number, since it uses less digits than its factorization.
31141012440402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30351864007 (or 30351864001 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 31141012440402 its reverse (20404421014113), we get a palindrome (51545433454515).
The spelling of 31141012440402 in words is "thirty-one trillion, one hundred forty-one billion, twelve million, four hundred forty thousand, four hundred two".
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