Base | Representation |
---|---|
bin | 1001000100000011001… |
… | …11010100100101100001 |
3 | 1002202210212000120102220 |
4 | 10202001213110211201 |
5 | 20100233011322423 |
6 | 355021044301253 |
7 | 31333041100530 |
oct | 4420147244541 |
9 | 1082725016386 |
10 | 311412214113 |
11 | 110084092710 |
12 | 5042b3a1829 |
13 | 2349b283120 |
14 | 11102a76317 |
15 | 81795259e3 |
hex | 48819d4961 |
311412214113 has 32 divisors (see below), whose sum is σ = 557493199872. Its totient is φ = 149328532800.
The previous prime is 311412214067. The next prime is 311412214117.
311412214113 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 311412214113 - 210 = 311412213089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311412214117) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 51847183 + ... + 51853188.
It is an arithmetic number, because the mean of its divisors is an integer number (17421662496).
Almost surely, 2311412214113 is an apocalyptic number.
311412214113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
311412214113 is a deficient number, since it is larger than the sum of its proper divisors (246080985759).
311412214113 is a wasteful number, since it uses less digits than its factorization.
311412214113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103700405.
The product of its digits is 576, while the sum is 24.
It can be divided in two parts, 311412 and 214113, that added together give a palindrome (525525).
The spelling of 311412214113 in words is "three hundred eleven billion, four hundred twelve million, two hundred fourteen thousand, one hundred thirteen".
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