Base | Representation |
---|---|
bin | 1001000100000011001… |
… | …11010100100101100000 |
3 | 1002202210212000120102212 |
4 | 10202001213110211200 |
5 | 20100233011322422 |
6 | 355021044301252 |
7 | 31333041100526 |
oct | 4420147244540 |
9 | 1082725016385 |
10 | 311412214112 |
11 | 11008409270a |
12 | 5042b3a1828 |
13 | 2349b28311c |
14 | 11102a76316 |
15 | 81795259e2 |
hex | 48819d4960 |
311412214112 has 48 divisors (see below), whose sum is σ = 651743647632. Its totient is φ = 145963008000.
The previous prime is 311412214067. The next prime is 311412214117. The reversal of 311412214112 is 211412214113.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311412214117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1003793 + ... + 1276880.
It is an arithmetic number, because the mean of its divisors is an integer number (13577992659).
Almost surely, 2311412214112 is an apocalyptic number.
311412214112 is a gapful number since it is divisible by the number (32) formed by its first and last digit.
It is an amenable number.
311412214112 is an abundant number, since it is smaller than the sum of its proper divisors (340331433520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311412214112 is a wasteful number, since it uses less digits than its factorization.
311412214112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2280951 (or 2280943 counting only the distinct ones).
The product of its digits is 384, while the sum is 23.
Adding to 311412214112 its reverse (211412214113), we get a palindrome (522824428225).
Subtracting from 311412214112 its reverse (211412214113), we obtain a palindrome (99999999999).
The spelling of 311412214112 in words is "three hundred eleven billion, four hundred twelve million, two hundred fourteen thousand, one hundred twelve".
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