Base | Representation |
---|---|
bin | 100011011001111101011101… |
… | …0110000111110100100100110 |
3 | 1111211200112101122010021002021 |
4 | 1012303322322300332210212 |
5 | 311304442110240044332 |
6 | 3022205305042133354 |
7 | 122412106520533201 |
oct | 10663727260764446 |
9 | 1454615348107067 |
10 | 311431212034342 |
11 | 90260265220134 |
12 | 2ab1955695125a |
13 | 104a0ab667827a |
14 | 56c94cb55c938 |
15 | 2601091b51c97 |
hex | 11b3ebac3e926 |
311431212034342 has 8 divisors (see below), whose sum is σ = 487457549271216. Its totient is φ = 148945362277272.
The previous prime is 311431212034279. The next prime is 311431212034351. The reversal of 311431212034342 is 243430212134113.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 311431212034298 and 311431212034307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3385121869893 + ... + 3385121869984.
It is an arithmetic number, because the mean of its divisors is an integer number (60932193658902).
Almost surely, 2311431212034342 is an apocalyptic number.
311431212034342 is a deficient number, since it is larger than the sum of its proper divisors (176026337236874).
311431212034342 is a wasteful number, since it uses less digits than its factorization.
311431212034342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6770243739902.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 311431212034342 its reverse (243430212134113), we get a palindrome (554861424168455).
The spelling of 311431212034342 in words is "three hundred eleven trillion, four hundred thirty-one billion, two hundred twelve million, thirty-four thousand, three hundred forty-two".
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