Base | Representation |
---|---|
bin | 100011011001111110110100… |
… | …0110000110000101101000000 |
3 | 1111211200210221002001220112210 |
4 | 1012303331220300300231000 |
5 | 311310014100042304440 |
6 | 3022210510442222120 |
7 | 122412242045252406 |
oct | 10663755060605500 |
9 | 1454623832056483 |
10 | 311434131213120 |
11 | 90261522aa9383 |
12 | 2ab1a0304b4940 |
13 | 104a11603a26a6 |
14 | 56c96c7127476 |
15 | 26011b307da80 |
hex | 11b3f68c30b40 |
311434131213120 has 224 divisors, whose sum is σ = 996344938431360. Its totient is φ = 82416202260480.
The previous prime is 311434131213059. The next prime is 311434131213187. The reversal of 311434131213120 is 21312131434113.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 310815330 + ... + 311815710.
It is an arithmetic number, because the mean of its divisors is an integer number (4447968475140).
Almost surely, 2311434131213120 is an apocalyptic number.
311434131213120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 311434131213120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (498172469215680).
311434131213120 is an abundant number, since it is smaller than the sum of its proper divisors (684910807218240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311434131213120 is a wasteful number, since it uses less digits than its factorization.
311434131213120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1002873 (or 1002863 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 30.
Adding to 311434131213120 its reverse (21312131434113), we get a palindrome (332746262647233).
The spelling of 311434131213120 in words is "three hundred eleven trillion, four hundred thirty-four billion, one hundred thirty-one million, two hundred thirteen thousand, one hundred twenty".
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